Question

Find the value of x, put y = -1/6 in y = 2x/3 + 1/3​

Answer 1

Answer:

x = -3/4

Step-by-step explanation:

substituting y as - 1/6

-1/6 = 2x/3 + 1/3

-1/6-1/3 = 2x/3

-1/2 = 2x/3

x = -1/2*3/2

x = -3/4

hope its helpful.. mark as brainliest :)

Answer 2

$\large\sf\underline{Given\::}$

• $\sf\:y=\frac{2x}{3}+\frac{1}{3}$

where :

• y = $\sf\:\frac{-1}{6}$

‎

‎

$\large\sf\underline{To\:find\::}$

• Value of x

‎

‎

$\large\sf\underline{Solution\::}$

$\sf\:y=\frac{2x}{3}+\frac{1}{3}$

‎

• Let's substitute the value of y

‎

$\sf\implies\:\frac{-1}{6}=\frac{2x}{3}+\frac{1}{3}$

‎

• LCM of 3 and 3 in RHS

‎

$\sf\implies\:\frac{-1}{6}=\frac{2x+1}{3}$

‎

• Now cross multiplying

‎

$\sf\implies\:\frac{-1}{6}=\frac{2x+1}{3}$

$\sf\implies\:6(2x+1)=3 \times (-1)$

‎

• Multiplying the terms

‎

$\sf\implies\:12x+6=-3$

‎

• Transposing +6 to other side it becomes -6

‎

$\sf\implies\:12x=-3-6$

$\sf\implies\:12x=-9$

‎

• Transposing 12 to other side it goes to denominator

‎

$\sf\implies\:x=\frac{-9}{12}$

‎

• Reducing it to lower term

‎

$\sf\implies\:x=\cancel{\frac{-9}{12}}$

$\small{\underline{\boxed{\mathrm\red{\implies\:x\:=\:\frac{-3}{4}}}}}$ ★

‎

‎========================

$\large\sf\underline{Verifying\::}$

$\sf\:y=\frac{2x}{3}+\frac{1}{3}$

‎

• Lets substitute the values of y and x

‎

$\sf\to\:\frac{-1}{6}=\frac{2}{3} \times \frac{-3}{4}+\frac{1}{3}$

$\sf\to\:\frac{-1}{6}=\frac{-6}{12} +\frac{1}{3}$

‎

• Now LCM of 12 and 3 in RHS

‎

$\sf\to\:\frac{-1}{6}=\frac{-6+4}{12}$

$\sf\to\:\frac{-1}{6}=\frac{-2}{12}$

$\sf\to\:\frac{-1}{6}=\cancel{\frac{-2}{12}}$

$\sf\to\:\frac{-1}{6}=\frac{-1}{6}$

$\small\fbox\orange{Hence\:Verified}$

‎

$\dag\:\underline{\sf So\:the\:required\:value\:of\:x\:is\:\frac{-3}{4}}$ ☑

‎

========================

‎

‎

!! Hope it helps !!