Question

Find the value of 'x'
Pythagoras theorem sum
please give me the answer of sum​

Answer 1

Step-by-step explanation:

By Pythagoras theorem,

EF^2 = ED^2 + DF^2

$(17) {}^{2} = x {}^{2} + 8 {}^{2}$

$289 = x {}^{2} + 64$

$x { }^{2} = 289 - 64$

$x {}^{2} = 225$

$x = 45$

ED = 45.

Answer 2

DEF is a right triangle, with angle D=90°, FE=17 units and DF=8cm.

Using Pythagoras theorem, which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides, we have:-

DF²+ED²=EF²

=>8²+x²=17²

=>x²=17²-8²

=>x²=(17-8)(17+8)=25×9

=>

$\sqrt{ {x}^{2} } = \sqrt{ {3}^{2} } \times \sqrt{ {5}^{2} }$

=>x=5×3=15

Thus, value of x = 15 units