Question

find the value of x ..referthe attachment

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Answer 1

Answer:

In triangle AOB:-

70°+60°+(1)=180°{property of a triangle}

(1)=50°

(5)=(1){vertically opposite angles}

(5)=50°

(2)+(1)=180°{property of a straight line}

(2)=130°

Now in triangle AOD:-

10°+130°+(3)=180°{property of a triangle}

(3)=40°

x=60°

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Answer 2

Hi mate

$\huge\underline{\mathfrak\red{A}\green {n}\mathfrak\blue {s}\purple{w}\mathfrak\orange{e}\pink {r}}$

In triangle AOB :

$\sf {70}^{°</p><p>} + {60}^{°</p><p>} + (1) = {180}^{ °</p><p>}$

$\sf(1) = 50 ^{°}$

$\sf(5) = (1)$

$\sf(5) = {50}^{ °}$

$\sf(2) + (1) = {180}^{°}$

$\sf(2) = {130}^{°}$