Question

find the value of x sin2x=sin60*cos30*-cos6*sin30*

Answer 1

is it cos 6 or cos 60

Answer 2

>sin2x=sin60cos30-cos60sin30
>sin2x=sin(60-30)
>sin2x=sin30

$2x = n\pi + {( - 1})^{n} 30$
$x = \frac{n\pi}{2} + {( - 1)}^{n} 15$