Question

Find the value of x so that -3/2 to the power 6 ×4/9to the power 3 = 1/2 to the power 3x​

Answer 1

Answer:

x = 0. (If I interpreted question correctly)

Step-by-step explanation:

Refer to the attachment.

Answer 2

Answer:

$\large\boxed{\sf{0}}$

Step-by-step explanation:

Given

${( - \frac{3}{2} )}^{6} \times {( \frac{4}{9} )}^{3} = {( \frac{1}{2} )}^{3x} \\ \\ = > {( \frac{3}{2} )}^{6} \times {( \frac{2}{3}) }^{ {2}^{3} } = {( \frac{1}{2} )}^{3x} \\ \\ = > {( \frac{3}{2} )}^{6} \times {( \frac{2}{3} )}^{6} = {( \frac{1}{2} )}^{3x} \\ \\ = > {( \frac{2}{3} )}^{ - 6} \times {( \frac{2}{3} )}^{6} = {( \frac{1}{2} )}^{3x} \\ \\ = > {( \frac{2}{3}) }^{6 - 6} = {( \frac{1}{2} )}^{3x} \\ \\ = > {( \frac{2}{3} )}^{0} = \frac{ {1}^{3x} }{ {2}^{3x} } \\ \\ = > {2}^{0} \times {2}^{3x} = 1 \times {3}^{0} \\ \\ = > {2}^{3x} \times 1 = 1 \times 1 \\ \\ = > {2}^{3x} = 1 \\ \\ = > {2}^{3x} = {2}^{0}$

Now, bases are same , therefore powers will be same.

$= > 3x = 0 \\ \\ = > x = 0$