Question

find the value of x so that :- (4/5))^-2 ÷ (-4/5)^-2 = (1)^3x​

Answer 1

Answer:

27 is the answer

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Answer 2

Step-by-step explanation:

${( - \frac{4}{5} })^{ - 2} \div ({ - \frac{ 4}{5} })^{ - 2} = {1}^{3x} \\ {a}^{m} \div {a}^{n} = {a}^{m - n} \\ = { \frac{ - 4}{5} }^{ - 2 - ( - 2)} = {1}^{3x} \\ = { \frac{ - 4}{5} }^{0} = {1}^{3x} \\ 1 = {1}^{3 \times 0}$

so the value of x=0