Find the value of x so that -6, x, 8 are in AP
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Step-by-step explanation:
so here. x,8,y is in GP so 8 = √xy ⇒ 64/x = y . .... i. and x,y,-8 in AP so 2y = x - 8 .... ii. using i and ii. we get. 128/x = x - 8. ⇒ 128 = x^2 - 8x.
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