Question

Find the value of x so that 8x – 4, 6x +2 and 2x +4 will form an AP.

Answer 1

Answer:

hope my answer help you

please follow me

Answer 2

Answer:

-2

Explanation:

Let a1 = 8x-4 a2 = 6x+2 and a3= 2x+4

d= a2-a1

 = 6x+2 -(8x-4)

 = 6x+2-8x+4

 = 6 - 2x

a3 = a1 + 2d

2x + 4 = 8x - 4 + 2(-2x + 6)

2x + 4 = 8x -4 -4 x + 12

2x + 4 = 4x + 8

4 - 8 = 4x - 2x

-4 = 2x

x = -4/2

x = -2