Question

Find the value of x so that 8x – 4, 6x +2 and 2x +4 will form an AP.


PLZZZZZZ ANSWER URGENT....

Answer 1

Answer:

8x+4 , 6x-2 , 2x+4 are in A.P

==> 6x-2 - (8x+4) = 2x+4 - (6x-2)

6x-2-8x-4 = 2x+4-6x+2

6x-8x-2x+6x = 4+2+4+2

2x=12

x=6

Please mark me as the brainliest

Hope it helps...

Answer 2

Answer:

Here common difference is,

6x+2-8x+4=2x+4-6x-2

-2x+6=-4x+2

=>2x=-4

=>x=-2

so

AP=-20, 10,0,----------