find the value of x so that the distance between the points (-3,4) and (x,--4) is 10
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3
ANSWER
Given: Points P(x,4),Q(9,10) and PQ=10
Distance formula: PQ=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
PQ
2
=(x
2
−x
1
)
2
+(y
2
−y
1
)
2
100=(9−x)
2
+(10−4)
2
=81+x
2
−18x+36
=117+x
2
−18x
100=117+x
2
−18x
x
2
−18x+17x=0 (solve this equation)
(x−1)(x−17)
x=1 or x=17.
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0
Answer:
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