Question

Find the value of x so that the distance between the points (-3,4) and (x,-4) is 10
(1)
(1)​

Answer 1

ANSWER

Given: Points P(x,4),Q(9,10) and PQ=10

Distance formula: PQ=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

PQ

2

=(x

2

−x

1

)

2

+(y

2

−y

1

)

2

100=(9−x)

2

+(10−4)

2

=81+x

2

−18x+36

=117+x

2

−18x

100=117+x

2

−18x

x

2

−18x+17x=0 (solve this equation)

(x−1)(x−17)

x=1 or x=17.

Explanation:

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