Question

find the value of x so that x+2,4x-6,3x-2 are three consecutive terms of an Ap​

Answer 1

Answer:

T2-T1=T3-T2

4x-6-(x+2)=3x-2-(4x-6)

3x-4=4-x

4x=8

x=2

Answer 2

The value of x = 3

Given :

x + 2 , 4x - 6 , 3x - 2 are three consecutive terms of an AP

To find :

The value of x

Concept :

If a , b , c are in AP then 2b = a + c

Solution :

Step 1 of 2 :

Write down the given terms

Here it is given that x + 2 , 4x - 6 , 3x - 2 are three consecutive terms of an AP

Step 2 of 2 :

Find the value of x

By the given condition

$\displaystyle \sf{ 2(4x - 6) = (x + 2) + (3x - 2)}$

$\displaystyle \sf{ \implies 8x - 12 =4x}$

$\displaystyle \sf{ \implies 8x - 4x = 12}$

$\displaystyle \sf{ \implies 4x = 12}$

$\displaystyle \sf{ \implies x = 3}$

Hence the required value of x = 3

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ If the middle term of a finite AP with 7 terms is 21 find the sum of all terms of the AP

https://brainly.in/question/30198388

2. find the 100th term of an AP whose nth term is 3n+1

https://brainly.in/question/22293445