Question

find the value of x square + 7x -1=0​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$x = \frac{ - 7 + \sqrt{53} }{2} or \frac{ - 7 - \sqrt{53} }{2}$

Step-by-step explanation:

${x}^{2} + 7x - 1 = 0$

This is a quadratic equation,

A quadratic equation is the equation that has the degree 2 and is in the form ax²+bx+c=0.

To find the value of x we have two methods,

$> middle \: term \: factorisation$

$> x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a}$

By using the formula for x,

${x}^{2} + 7x - 1 = 0$

$x = \frac{ - 7 + - \sqrt{49 - 4.1. - 1} }{2.1}$

$x = \frac{ - 7 + - \sqrt{53} }{2}$

Therefore we get two values,

$x = \frac{ - 7 + \sqrt{53} }{2}$

Or

$x = \frac{ - 7 - \sqrt{53} }{2}$