Math, asked by r7azvgeet7arejj, 1 year ago

Find the value of x (square root of 32) ÷ 2^x+1 = 1

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Answered by utpalmrinal

0

√32÷2^(x+1)=1 =2^5/2÷2^x+1=1 =2^5/2-x-1=2^0 So, 5/2-x-1=0 Sox=5/2-1=3/2

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