Question

find the value of x such that

2 cosec^2 30°+x.sin^2 60°-3/4 tan^2 30°=10​

Answer 1

Answer:

The value of X=3

Hope this answer will help you

Answer 2

Answer:

3

Step-by-step explanation:

2 cosec^2 30°+x.sin^2 60°-3/4 tan^2 30°=10

2(2)^2+x(√3/2)^2-3/4(1/√3)^2=10

2(4)+x(3/4)-(3/4)(1/3)=10

8+x(3/4)-1/4=10

8-1/4+x(3/4)=10

31/4+x(3/4)=10

x(3/4)=10-31/4

x(3/4)=40-31/4 (by doing LCM)

x(3/4)=9/4

x(3)=9 (denominators are same on both sides,so, cancelled)

x=9/3

x=3