Math, asked by ritexa93, 12 hours ago

Find the value of x such that (6/7)²x X (6/7)x+⁵ = (6/7)x-³​

Answers

Answered by rudrauparkar
4

Step-by-step explanation:

( 6 /7 ) ^2x × ( 6 / 7 ) ^x+5

= ( 6 / 7 )^2x + x + 5. ( X^m × X ^n = X ^m+n )

= ( 6 / 7 ) ^3x + 5

since both sides base is equal

eliminating base, we get

3x + 5 = x - 3

3x - x = -3 -5

2x = -8

x = -8 / 2

x = -4

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