Question

Find the value of x
$10 - \frac{5(1 + x)}{3} + \frac{3x + 1}{5} = 0$
​

Answer 1

Step-by-step explanation:

$heya.......$

$10 - \frac{5 + 5x}{3} + \frac{3x + 1}{5} = 0$

$10 - \frac{25 - 25x + 9x + 3}{15} = 0$

$10 - \frac{22 - 16 x}{15} = 0$

$\frac{128 - 16x}{15} = 0$

$x = \frac{ - 128}{-16}$

$x = 8$

$HOPE$

$IT$

$HELPS$

$UH !!!!!!!$

Answer 2

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore x=8}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about $10 - \frac{5(1 + x)}{3} + \frac{3x + 1}{5} = 0$

• We have to find the value of from this eqn.

$\underline \bold{given :} \\ \implies 10 - \frac{5(1 + x)}{3} + \frac{3x + 1}{5} = 0 \\ \\ \underline \bold{ to \: find : } \\ \implies value \: of \: x = ?$

• According to given question :

$\bold{for \: solving \: this \: question} \\ \implies 10 - \frac{5(1 + x)}{3} + \frac{3x + 1}{5} = 0 \\ \\ \bold{ breaking \: bracket} \\\implies 10 - \frac{5 + 5x}{3} + \frac{3x + 1}{5} = 0 \\ \bold{take \: lcm \: of \: 3 \: and \: 5} \\ \implies \frac{10 \times 15 -5(5 + 5x) + 3(3x + 1) }{15} = 0 \\ \\ \implies \frac{150 - 25 - 25x + 9x + 3}{15} = 0 \\ \\ \implies 150 - 25 + 3 - 25 x+ 9x = 0 \\ \\ \implies 128 - 16x = 0 \\ \\ \implies - 16x = - 128 \\ \\ \implies x = \frac{ \cancel{- 128}}{ \cancel{- 16}} \\ \\ \bold{\implies x = 8} \\ \\ \huge\bold{ \underline{ \underline{verification : }}} \\ \\ \implies 10 - \frac{5(1 + x)}{3} + \frac{3x + 1}{5} = 0 \\ \\ \bold{ putting \: value \: of \: x \: in \: lhs} \\ \implies 10 - \frac{5(1 + 8)}{3} + \frac{3 \times 8 + 1}{5} \\ \\ \implies 10 - \frac{5 \times 9}{3} + \frac{24+ 1}{5} \\ \\ \implies10 - 15 + 5 \\ \\ \implies \cancel{15 - 15} = 0 \\ \\ \: \: \: \: \: \: \: \: \: \huge \bold{ \underline{ \underline{verified : }}}$