find the value of x
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⇒ (2^x)^2 - (2)^x * (2)^3 + (2)^4 = 0
Let 2^x = a
⇒ a^2 - a * 8 + 16 = 0
⇒ a^2 - 8a + 16 = 0
⇒ a^2 - 4a - 4a + 16 = 0
⇒ a(a - 4) - 4(a - 4) = 0
⇒ (a - 4)(a - 4) = 0
⇒ (a - 4)^2 = 0
⇒ a = 4.
Then, 2^x = 4
⇒ 2^x = 2^2
⇒ x = 2.
Therefore, the value of x = 2.
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