Math, asked by Anonymous, 1 month ago

find the value of x :-

( {3}^{ - 2}  \times  {4}^{ - 2} ) {}^{ - 3}  =  {12}^{x}
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Answered by Thatsomeone
6

 \tt {({3}^{-2}×{4}^{-2})}^{-3} = {12}^{x} \\ \\ \tt \implies {({3}^{-2})}^{-3} + {({4}^{-2})}^{-3} = {(4×3)}^{x} \\ \\ \tt \implies {3}^{6} × {4}^{6} = {3}^{x} × {4}^{x} \\ \\ \tt \therefore \boxed{\bold{\underline{\red{\tt x = 6 }}}}

Answered by Anonymous
1

Answer:

Thank you so much but I am deleting this account.

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