Question

Find the value of x

$(3/5)^{-3}$ × $(3/5)^{5}$ = $(3/5)^{2x+1}$

Answer 1

$\huge\star{\red{\underline{\mathfrak{Answer}}}}$

See, as the numbers are same numbers get cancelled of and only the superscript is left .

Answer 2

Step-by-step explanation:

We know that,

If bases are equal then exponents are also equal...

so,

According to the question,

=(3/5)^(-3) × (3/5)^5 = (3/5)^2x+1

so,

= -3+5 = 2x+1

= 2 = 2x+1

= 2-1 = 2x

= 1 = 2x

= 1/2 = x

Therefore the value of x = 1/2.....

Hope!!! it helps you....