Math, asked by aaravsundrani14, 12 hours ago

Find the value of x
 {4}^{x \: }  +  {4}^{x + 1}  = 80
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Answers

Answered by anbukodij
0

4^x+4^x+1=80

if x=1

4+16=20

so xis not equal to 1

if x=2

4^2+4^2+1

=16+4^3

=16+64=80

so x=2

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