Question

find the value of x
$\frac{1}{6!} + \frac{1}{7!} = \frac{x}{8!}$
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Answer 1

$\huge \bf \underline{ \underline{\bigstar Solution }}$

$\rightarrow \sf\frac{1}{6!} + \frac{1}{7!} = \frac{x}{8!}$

$\rightarrow \sf \: \frac{1}{6!} + \frac{1}{7 \times 6!} = \frac{x}{8!}$

$\rightarrow \sf \: \frac{1}{6!} (1 + \frac{1}{7 } )= \frac{x}{8 \times 7 \times 6!}$

$\rightarrow \sf ( \frac{8}{7 } )= \frac{x}{8 \times 7 }$

$\rightarrow \sf8 = \frac{x}{8}$

$\sf \rightarrow x = 64$

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$\sf \: Therefore \: the \: value \: of \: x \: is \: 64$

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Answer 2

Answer:

QUESTION- Find the value of x

$\frac{1}{6!} + \frac{1}{7!} = \frac{x}{8!}$

SOLUTION-

$\frac{1}{6} + \frac{1}{7} + = \frac{x}{8} \\ !8( \frac{1}{6!} + \frac{1}{7!} ) = x \\ \frac{8!}{6!} + \frac{8!}{7!} = x \\ \frac{8 \times 7 \times 6!}{6!} + \frac{8 \times 7!}{7!} = x \\ 8 \times 7 + 8 = x \\ 56 + 8 = x \\ 64 = x \\ x = 64$

THEREFORE, X = 64.

$\large \star\underline {\underline\purple {\mathfrak {hope \: it \: helps!}}} \star$