Question

find the value of x =
$( \frac{5}{7}) {}^{2} \div ( \frac{5}{7}) {}^{3x + 1} = ( \frac{5}{7} ) {}^{4}$
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Answer 1

Step-by-step explanation:

2-3x+1=4

2+3x=4-1

3x=3-2

x=1/3

Answer 2

comparing the bases,

2-3x+1=4

3-3x=4

-3x=4-3

x=1/-3

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