Question

find the value of x
$if 9 \sqrt{x } = \sqrt{12} + \sqrt{147}$
LHS=RHS

Answer 1

under root 12 + under root 147
2 under root 3 + 7 under root 3
9 under root 3
we got the value of x =3

Answer 2

under root 12 + under root 147
2 under root 3 + 7 under root 3
9 under root 3
we got the value of x is equals to 3