Question

Find the value of x, $\sf{\bigg[ \dfrac{5 {x}^{2} - 10}{12 } \bigg] }$

Please tell the solution also. ​

Answer 1

Given :-

• Equation :- $\sf{\bigg[ \dfrac{5 {x}^{2} - 10}{12 } \bigg] }$

Have to Find :-

• The value of ' x '

Solution :-

Taking the whole equation = 0

According to the factor Theorem

$\sf{\bigg[ \dfrac{5 {x}^{2} - 10}{12 } \bigg] }$

↬ 5x² - 10/ 12 = 0

↬ 5x² - 10 = 0 × 12

↬ 5x² - 10 = 0

↬ 5x² = 10

↬ x² = 10/5

↬ x² = 2

↬ x = √2

Therefore, the value of ' x ' is √2

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Answer 2

Step-by-step explanation:

Given Equation:-

⠀⠀⠀⠀ $\sf{\bigg[ \dfrac{5 {x}^{2} - 10}{12 } \bigg] }$

To find:-

value of x

Solution:-

use factor theorem

take the value of equation =0

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow \left [\dfrac {5x^2-10}{12}\right]=0$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow \dfrac {5x^2-10}{12}=0$

• using cross multiplication

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow 5x^2-10=0$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow 5x^2=10$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow x^2=\dfrac {10}{5}$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow x^2=2$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow x=\sqrt {2}$

$\\\\\therefore\sf x=\sqrt {2}.$