Math, asked by anonymousthanks1, 1 year ago

find the value of 'x'
$\sqrt{x + 3 - 4 \sqrt{x + 1} } + \sqrt{x + 8 - 6 \sqrt{x - 1 } } = 1$

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Answered by mohibulhoque1

3

hope it will help you. Thank you.....

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anonymousthanks1: thanks

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