find the value of x the point are (-5,7),(x,5)&(0,2) are collinear
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Let A=(-5,7) B=(x,5) and C=(0,2)
slope of AB=5-7/x+5
=-2/x+5
slope of BC=2-5/0-x
=-3/-x
slope of AB=slope of BC
-2/x+5=-3/-x
-2(x)=3(x+5)
-2x=3x+5
-2x-3x=5
-5x=5
x=-5/5
x=-1
slope of AB=5-7/x+5
=-2/x+5
slope of BC=2-5/0-x
=-3/-x
slope of AB=slope of BC
-2/x+5=-3/-x
-2(x)=3(x+5)
-2x=3x+5
-2x-3x=5
-5x=5
x=-5/5
x=-1
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Hey !!
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Check the attachment.
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