Find the value of x. TRIANGLE LMN , LN =x , LM=7 , MN=24
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LM=9cm
MN=12cm
LN=15cm
∴PM=4.5cm
QN=7.5cm
And we know that the line joining the mid points of the two sides of a triangle is parallel to the third side and is equal to half of it.
∴PQ=
2
1
MN=6cm
(i)Perimeter of trapezium MNQP=(4.5+7.5+12+6)
=24+6
=30cm
(ii)Area of trapezium=
2
1
×(sum of parallel sides)× (height)
=
2
1
×(12+6)×4.5
=9×4.5
=40.5cm
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