find the value of x using quadratic formula for abx square +( b square minus ac )x minus bc equals to zero
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Given: abx2+(b2−ac)x−bc=0
Factorizing the given equation,
⟹abx2+b2x−acx−bc=0
⟹bx(ax+b)−c(ax+b)=0
⟹(bx−c)(ax+b)=0
Solving the above equation for x, we get
⟹(bx−c)=0 or (ax+b)=0
⟹x=bc or x=a−b
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