find the value of x when 1+6+11+....+x=148
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4
Answer:
x=36
Step-by-step explanation:
formula is sn=n/2[2a+(n-1)d]
:148=n/2[2(1)+(n-1)5]
296=(2+5n-5)n
296=(-3+5n)n
296=5n^2-3n
5n^2-3n-296=0
factorize
formula is minus b plus or minus rootof b^2-4ac/2a
substitute
a=5
b=-3
c=-296
3 plus or minus root of 9+5920
now root of 5929
=77
3+77/10 or 3-77/10
80/10 since a=5;2a=10 or -74/10
8
8 th term is the x value
it means 36
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