Question

find the value of x when (√3+√2)^x+(√3-√2)^x=10

Answer 1

if x=2 it is possible
(√3+√2)^x+(√3-√2)^x
if x=2
3+2+3+2+2root6-2root6
=10

Answer 2

Substituting x= 2

(√3+√2)^2 + (√3-√2)^2

(√3)^2+ 2*√3*√2+(√2)^2 + (√3)^2 -2*√3*√2 +(√2)^2

3+2√6+2+3–2√6+2

3+3+2+2 =10

L H.S = R.H.S

x=2

Ans : 2