find the value of x when (√3+√2)^x+(√3-√2)^x=10
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Answered by
2
if x=2 it is possible
(√3+√2)^x+(√3-√2)^x
if x=2
3+2+3+2+2root6-2root6
=10
(√3+√2)^x+(√3-√2)^x
if x=2
3+2+3+2+2root6-2root6
=10
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Answered by
5
Substituting x= 2
(√3+√2)^2 + (√3-√2)^2
(√3)^2+ 2*√3*√2+(√2)^2 + (√3)^2 -2*√3*√2 +(√2)^2
3+2√6+2+3–2√6+2
3+3+2+2 =10
L H.S = R.H.S
x=2
Ans : 2
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