Question

find the value of x when 8×2^x+2=32​

Answer 1

8•2^(n+2)=32

So let’s go ahead with the first option

8•2^n+2=32

8•2^n=30

2^n=15/4

n•ln(2)=ln(15/4)

n=ln(15/4)/ln(2)

Option 2

8•2^(n+2)=32

2^(n+2)=4

(n+2)ln(2)=ln(4)

n+2=ln(4)/ln(2)

n+2=2

n=0

I hope this helps you

please mark me as brainliest

please follow me

I will see for your reply

Answer 2

Answer:

x=0

Step-by-step explanation:

8*2^x+2=32

2^x+2=32/8

2^x+2=4

2^(x+2)=2^2

Bases are same so ignore bases

x+2=2

x=2-2

x=0