Find the value of x when:
a.) in a rectangle, L=3x, B=x and Perimeter = 48 units
b.) in a triangle, each side=x-2 and perimeter = 15 units
c.) in a rectangle, four sides are x-2 , 2x-3 , x-2 , 2x-3 and Perimeter = 8 units
Answers
Answer: a) x = 6 units, b) x=7units, c) x=3 units
Step-by-step explanation:
(A) l = 3x and b = x
perimeter = 48 units
Perimeter = 2(l+b)
48 = 2(3x+x)
48 = 2(4x)
48 = 8x
x = 48/8
x = 6 units
(B) Side = x-2
perimeter = 15 units
perimeter = side a + side b + side c
15 units = x-2 + x-2 + x-2
15 = x+x+x-2-2-2
15 = 3x - 6
Adding 6 on both the sides
15+6 = 3x - 6+6
21 = 3x
x = 7 units
(C) sides of rectangle = x-2, 2x-3
perimeter = 8 units
perimeter = 2(l+b)
8 units = 2(x-2 + 2x-3)
8 units = 2(x+2x-2-3)
8 units = 2(3x-5)
8 units = 6x-10
Adding 10 on both the sides
8+10= 6x -10+10
18 = 6x
x = 18/6
x = 3 units
Answer:
a) Here, Perimeter of rectangle = 2(L+B)
48 = 2(3x+x)
48 = 2× 4x
48 = 8x
48/8= x
x = 6
b) here, each side is x-2 therefore it is Equilateral triangle
Perimeter of Equilateral triangle = 3× side
15 = 3 (x-2)
15 = 3x - 6
15+6 = 3x
21/3= x
x = 7
c) L= 2x-3 and B = x-2
perimeter of rectangle = 2(L+B)
8 = 2[(2x-3) +(x-3) ]
8 = 2(2x-3+x-3)
8 = 2(3x-5)
8 = 6x-10
8+10 = 6x
18/6 = x
x = 3