Question

Find the value of X , when in the AP given 2+ 6+ 10+...…..+ X = 1800.

Answer 1

Step-by-step explanation:

$hello \: buddy \\ lets \: solve \: this \: beautiful \: question$

Here given that:-

a = t1 = 2

d = t2-t1 = 6-2 = 4

$tx = a + (n - 1)d$

$1800 = 2 + (x - 1)4$

$1800 = 2 + 4x - 4$

$x \: = \: \frac{1802}{4}$

$x = 450.5 = 450$

Hope it helps uh!