Question

find the value of x when

logx64=3/2
​

Answer 1

Answer:

(995635)^(2.66)

8;15;7;20

(4*z^2)/9-(25/36) = 0

x-(1/2) = x-(9/11)

((3/(x^7))*x)/6 = 0

Answer 2

Step-by-step explanation:

Given:-

logx64=3/2

To find:-

Find the value of x ?

Solution:-

Given that

logx64=3/2

Here x is the base

We know that

log a N = x =>a^X = N

So logx64=3/2 can be written as

=>x^(3/2) = 64

=>(x^(1/2))^3 = 64

(Since , (a^m)^n = a^(mn)

=>(x^(1/2))^3 = 4×4×4

=>(x^(1/2)^3 = 4^3

On Comparing both sides then

=>x^(1/2) = 4

On squaring both sides then

=>[x^(1/2)]^2 = 4^2

=>x^(2/2) = 4×4

=>x^1 = 16

=>x = 16

Therefore, x = 16

Answer :-

The value of x for the given problem is 16

Check:-

If x = 16 then

log 16 (64)

Here base 16

=>log(4^2) (4^3)

=>3/2 log (4) 4

=>3/2 ×1

=>3/2

Verified the given relation

Used formulae:-

• log a N = x =>a^X = N
• Where, a is the base
• (a^m)^n = a^(mn)
• log (a) a =1
• Where (a) is the base