Question

find the value of x , when sin(sin -1 3/5 + -1 x ) = 1​

Answer 1

Step-by-step explanation:

As i understand ur question

$\sin( \sin ^{ - 1} (\frac{3}{5} - \frac{1}{x} ) = 1 \\ \\ (\frac{3}{5} - \frac{1}{x} ) = 1 \\ \\ \frac{3}{5} - 1 = \frac{1}{x} \\ \\ \frac{ - 2}{5} = \frac{1}{x} \\ \\ x = - \frac{5}{2}$

$use \: this \: formula \: \\ \sin(sin ^{ - 1} x) = x$

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