Question

find the value of x when.
${3}^{x} = \sqrt{3} \div 9$

Answer 1

☆Hello friend☆

${3}^{x} = {3}^{ \frac{1}{2} } \div {3}^{2} \\ {3}^{x} = {3}^{ \frac{1}{2} - 2 } \\ {3}^{x} = {3}^{ \frac{ - 3}{2} }$

Henc, x = -3/2

Hope it helps

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