Question

find the value of x when the wheatstone network is balanced ?? P=500ohm. Q=800ohm. R=x+400ohm S=1000ohm​

Answer 1

Answer:

x = 225 ohm

Explanation:

by using formula

P / Q = R / S

500/ 800 = x+ 400 / 1000

5/ 8 = x + 400 / 1000

1800 / 8 = x

x = 225 ohm

Answer 2

Given:

$\[P = 500ohm\]$

$\[Q = 800ohm\]$

$\[R = x + 400ohm\]$

$\[S = 1000ohm\]$

To Find: Value of $x$

Solution:

According to the Wheatstone bridge formula,

$\[\frac{P}{Q} = \frac{R}{S}\]$

Therefore,

$\[\frac{{500\Omega }}{{800\Omega }} = \frac{{x + 400\Omega }}{{1000\Omega }}\]$

$\[x + 400\Omega = \frac{{500\Omega \times 1000\Omega }}{{800\Omega }}\]$

$\[x + 400\Omega = 625\Omega \]$

$\[x = 625\Omega - 400\Omega \]$

$\[x = 225\Omega \]$

Hence, the value of $x$ is $\[225\Omega \]$.