Question

find the value of x when the wheatstone network is balanced ?? P=500ohm. Q=800ohm. R=x+400ohm S=1000ohm​

Answer 1

Answer:

225 is answer by apply P/Q=R/S.

Answer 2

Answer:

The value of x is 225Ω.

Explanation:

Given is a Wheatstone Bridge network of resistors which is in a balanced state.

The magnitude of the given resistors is as follows,

P=500Ω Q=800ΩS=1000Ω and R=x+400Ω (because x is in series with the 400Ω resistor.)

Condition for the balanced Wheatstone bridge is

P×S=Q×(400+x)

On substituting the values,

$500\times 1000=800\times(400+x)\\x=225\Omega$

Hence, The required value of x is 225Ω