find the value of x when
xcosA × cot(90+A) +cosec(90+A) = sin(90+A)
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actually my photos were not adjusting so that,s why see the question is much clear I would say just understand the formula and think it in coordinate that if sin(90+A) is given now in first quadrant all will be+be ,II quadrant sinand cosec,III quadrant tan and cot ,IV quadrant cos and sec now sin lies between 90 to 180 if it will rotate anticlockwise then it will be +ve so rotate it
well now it will lies in I quadrant so all are +ve .so we have to find a specific value understanding the concept.so once again rotate then it will come cosA please see in the third figure .so mark me as branliest if you think
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