Question

Find the value of x where BC is parallel to AD.

No rubbish...or if you followed than you are _______ dash.

You must have to bring answer 50cm.
Those who will give the answer with proper solution he/she is great.​

Answer 1

considering quadrilateral ABCE,

<CEA=90=<CBA

since opposite angles are 90° ABCE is a rectangle.

so,

• CB=EA(rectangle opp sides are equal)
• CB=14cm, so, EA=14cm
• DA=28-14=14cm.
• so, CB=EA=DE

now, considering triangle ️ ACD,

• AE=DE (proved)
• so CE is the median.

now considering triangle ️CEA and triangle ️ CED,

• CE=CE (common)
• AE=ED (median separates base equally)
• <CEA=<CED=90° (Given)

so, triangle ️CEA is congruent to triangle ️CED by RHS similarity.

so, CA=CD=50cm

x=50cm

hope it helps!