. Find the value of x which is equidistant from the points A (6,5) and B(4, 5).
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the value of X which is equidistant from A and B is 5
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Co-ordinates of point x is: x( 5, 5)
Step-by-step explanation:
If x is equidistant from A and B, half of AB = distance between x and B.
AB = √(6-4)²+(5-5)²
AB = √4
AB = 2 units
Therefore, half of AB =1 unit . point x = 1 unit from any point a or b
now, we know that line AB is parallel to x axis at a distance of 5 as both a and b have 5 as y co-ordinate.Therefore x also has to have 5 as y co-ordinate.
But we also know that x is one unit away from each of the points(4,5) and (6,5)
Now we can say that x is (5,5).
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