Question

find the value of x , which satisfy 3-5x/3-4x = 5x-1/4x-1

Answer 1

$\frac{3 - 5x}{3 - 4x} = \frac{5x - 1}{4x - 1} \\ (3 - 5x)(4x - 1) = (5x - 1)(3 - 4x) \\ 12x - 3 - 20 {x}^{2} + 5x = 15x - 20 {x}^{2} - 3 + 4x \\ 17x = 19x \\ 2x = 0 \\ x = 0$