Find the value of x which satisfy the equation sin-1x +sin-1(1-x) =cos-1x
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Answer:
Given
sin−1(x)+sin−1(1−x)=cos−1(x)
sin−1(1−x)=cos−1(x)−sin−1(x)⇒(1−x)=sin[cos−1(x)−sin−1(x)]
Using
sin−1(x)+cos−1(x)=π2
So
(1−x)=sin[π2−2sin−1(x)]=cos(2sin−1(x))=cos(cos−1(1−2x2))
Using
2sin−1(x)=cos−1(1−2x2)
So
(1−x)=(1−2x2)⇒2x2−x=0
So
2x2−x=0⇒x=0,x=12
Now Put into Original Equation we get x=12 and
x=0 satisfy the Given equation
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hi frnd
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