find the value of x with a complete solution.
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sachin11211:
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HI, friend !!
here is your answer !!
this is JEE question !!
look this attachment hope it help you !!
thanks !!
Rj
here is your answer !!
this is JEE question !!
look this attachment hope it help you !!
thanks !!
Rj
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Let : a = 5 + 2√6 ... so that ... 5 - 2√6 = 1/a.
Also, let : n = x² - 3.
Then, the given equation becomes :
... aⁿ + ( 1/ aⁿ ) = 10
∴ (aⁿ)² + 1 = 10(aⁿ)
∴ 1(aⁿ)² - 10(aⁿ) + 1 = 0 ... like ax²+bx+c = 0
∴ by Quadratic Formula,
... aⁿ = [ -b ± √(b²-4ac) ] / (2a) = [ 10 ± √(100- 4) ] / 2
∴ aⁿ = [ 10 ± 4√6 ] / 2 = 5 ± 2√6
∴ ( 5 + 2√6 )ⁿ = ( 5 + 2√6 ) or ( 5 - 2√6) ∴ n = 1 or -1
∴ x² - 3 = 1 or -1
∴ x² = 4 or 2
∴ x = ± 2 or ± √2 .................. Ans.
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