find the value of x,
with explanation
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Angle
OAB=OBA(RADIUS OF THE CIRCLE)
AOB=180°-(OAB+OBA) (ANGLE SUM PROPERTY)
AOB=180°-(35+35)
AOB=180°-70°
AOB=110°
REFLEX AOB =360-110
=250°
x=1/2(reflex AOB)
x=1/2*250
x=125°
OAB=OBA(RADIUS OF THE CIRCLE)
AOB=180°-(OAB+OBA) (ANGLE SUM PROPERTY)
AOB=180°-(35+35)
AOB=180°-70°
AOB=110°
REFLEX AOB =360-110
=250°
x=1/2(reflex AOB)
x=1/2*250
x=125°
Answered by
1
OAB=OBA ⇒(radius of circle,)
∠AOB+∠OAB+∠OBA=180° ⇒(sum of the angles in a triangle equals 180°)
∠AOB+35°+35°=180°
∠AOB+70°=180°
∠AOB=180°-70°⇒x=110°,
reflex∠AOB/2=x
(360°-110°)/2=250°/2=125°
x=125°
∠AOB+∠OAB+∠OBA=180° ⇒(sum of the angles in a triangle equals 180°)
∠AOB+35°+35°=180°
∠AOB+70°=180°
∠AOB=180°-70°⇒x=110°,
reflex∠AOB/2=x
(360°-110°)/2=250°/2=125°
x=125°
sivaprasath:
thanks
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