Math, asked by shinuRg, 1 year ago

Find the value of x
x^2-4x+3=0​

Answers

Answered by shivika5622
1

Answer:

x^2-3x-x+3=0

x(x-3)-1(x-3)=0

(x-1)(x-3)=0

x-1=0

x=1

x-3=0

x=3

x=1,3..✌️

Answered by ndpathak
1

Answer:

x2-4x+3=0

x2-3x-x+3=0

x(x-3)-1(x-3)=0

(x-1)(x-3)=0

x-1=0

& x-3=0

then x=1,3 ANSWER

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