Find the value of x-- (x-5), (x+2)=(x-4), (x-8)
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(1) X-5 = 0
X = 5
(2) (X+2)=(X-4)
X +2 = X-4
X - X = -4-2
= -6
(3) X-8 = 0
X = 8
X = 5
(2) (X+2)=(X-4)
X +2 = X-4
X - X = -4-2
= -6
(3) X-8 = 0
X = 8
Answered by
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{if (,) means x...}
x^2 + 2x -5x -10 = x^2-8x -4x+ 32
= -3x -10 = -12x + 32
= -3x + 12x = 32 + 10
= 9x = 42
x = 42/9
=4.6
x^2 + 2x -5x -10 = x^2-8x -4x+ 32
= -3x -10 = -12x + 32
= -3x + 12x = 32 + 10
= 9x = 42
x = 42/9
=4.6
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