Question

Find the value of x: X+x+2/3 = 1+x-1/2

Answer 1

Answer:

$x + x + \frac{2}{3} = 1 + \frac{x - 1}{2} \\</p><p></p><p>\\</p><p> 2x + \frac{2}{3} = 1 + \frac{ x - 1}{2} \\ </p><p></p><p>\\</p><p> \frac{2x}{1} - ( \frac{x - 1}{2} ) = 1 - \frac{2}{3} \\</p><p></p><p>\\</p><p> \frac{2x}{1} - \frac{x + 1}{2} = \frac{1}{1}-</p><p>\frac{2}{3} \\</p><p></p><p>\\</p><p>\frac{4x- x +1}{2} = \frac{3 - 2}{3}\\</p><p></p><p>\\</p><p>\frac{ 3x + 1}{2} = \frac{ 1}{3} \\</p><p></p><p>\\</p><p>3x + 1 = \frac{1}{3} × 2 \\</p><p></p><p>\\</p><p>3x + 1 = \frac{2}{3} \\</p><p></p><p>\\</p><p>3x = \frac{2}{3} - \frac{1}{1}\\</p><p></p><p>\\</p><p>3x = \frac{2 - 3}{3} \\</p><p></p><p>\\</p><p>3x = \frac{-1}{3}\\</p><p></p><p>\\</p><p>x = \frac{-1}{3 ×3}\\</p><p></p><p>\\</p><p>x= \frac {-1}{9}$

Answer 2

Answer:

$\implies \: x + x + \dfrac{2}{3} = 1 + \dfrac{x - 1}{2} \\ \\ \\ \implies2x + \frac{2}{3} = 1 + \frac{x - 1}{2} \\ \\ \\ \implies \frac{2x}{1} - \left( \frac{x - 1}{2}\right) = \frac{1}{1} - \frac{2}{3} \\ \\ \\ \implies \frac{4x - x + 1}{2} = \frac{3 - 2}{3} \\ \\ \\ \implies \frac{3x + 1}{2} = \frac{1}{3} \\ \\ \\ \implies3x + 1 = \frac{2}{3} \\ \\ \\ \implies3x = \frac{2}{3} - \frac{1}{1} \\ \\ \\ \implies3x = \frac{2 - 3}{3} \\ \\ \\ \implies3x = \frac{ - 1}{3} \\ \\ \\ \implies \: x = \frac{ - 1}{3 \times 3} \\ \\ \\ \implies \: x = \frac{ - 1}{9}$