Question

find the value of x+x(x)^2​

Answer 1

Step-by-step explanation:

x

2

+x−182=0

⇒ x

2

+14x−13x−182=0

⇒ x(x+14)−13(x+14)=0

⇒ (x+14)(x−13)=0

⇒ x+14=0 and x−13=0

∴ x=−14,13